Problem 40 Let \(A\) be a set with 12 eleme... [FREE SOLUTION] (2024)

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Chapter 2: Problem 40

Let \(A\) be a set with 12 elements. (a) Find the number of subsets of \(A\). (b) Find the number of subsets of \(A\) having one or more elements. (c) Find the number of subsets of \(A\) having exactly one element. (d) Find the number of subsets of \(A\) having two or more elements. [Hint: Usethe answers to parts (b) and (c).

Short Answer

Expert verified

The number of subsets of A is \(2^{12}\), the number of subsets having one or more elements is \(2^{12}-1\), the number of subsets having exactly one element is \(12\), and the number of subsets having two or more elements is \(2^{12} - 1 - 12\).

Step by step solution

01

Understanding the Power Set

The number of subsets of a set with 'n' elements is given by the formula for the power set, which is the set of all subsets including the empty set, calculated as \(2^n\). For a set A with 12 elements, we raise 2 to the power of 12.

03

Exclude the Empty Set for Non-empty Subsets

To find the number of subsets having one or more elements, exclude the empty set from the total number of subsets. This means subtracting 1 from \(2^n\) because there's only one empty set.

04

Determine Single-element Subsets

The number of subsets with exactly one element is equal to the number of elements in the original set A since each element can form a subset. This gives us 12 one-element subsets.

05

Calculate Subsets with Two or More Elements

To find the number of subsets with two or more elements, subtract the number of one-element subsets (from Step 4) and the empty set from the total number of subsets. Use the answers from parts (b) and (c) in this calculation.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Set

When dealing with sets in mathematics, a crucial concept to understand is the power set. The power set of any given set A is a larger set that contains all possible subsets of A, including the empty set and A itself. For example, if we imagine a simple set containing three elements, say {a, b, c}, its power set would include all combinations from no elements (the empty set) to all elements ({a, b, c}).

To find out how many subsets a set has, we can use the formula related to the power set, which states that if a set has 'n' elements, the number of subsets (the size of the power set) is given by the mathematical expression \(2^n\). This is because each element can either be included in or excluded from a subset, effectively giving us two options per element. So, when a set has 12 elements, like in our exercise, by raising 2 to the 12th power, we get \(2^{12}\) which equals 4096. This includes every possible subset, from the one with zero elements (empty set) to the one with all 12 elements.

Set Theory

Set theory is the branch of mathematical logic that studies sets, which are collections of objects. It is the foundational basis for many areas of mathematics. Sets can be anything: numbers, people, letters, etc. For instance, a set A with 12 elements could represent 12 different numbers or 12 unique letters of the alphabet.

The beauty of set theory lies in its ability to apply uniform rules to these collections, such as finding the number of subsets as seen in the exercise. In set theory language, a subset is a set where all of its elements are contained within another set. Importantly, under set theory, the empty set is considered a subset of any set, contributing to the total count when we calculate the power set. It's also worth noting that the principles of set theory are widely applied across various fields such as statistics, computer science, and logic.

Combinatorics

Combinatorics is a field of mathematics that deals with counting, arrangement, and combination of elements within sets, proving essential for solving our exercise. It comes into play, particularly when finding the number of subsets with certain properties – such as those with exactly one element or two or more elements.

In our exercise, combinatory logic was used to determine different types of subsets. For instance, single-element subsets are directly related to the number of elements in the set. Since set A has 12 elements, there are 12 possible subsets each containing exactly one element. On the other hand, for subsets with two or more elements, we consider the full range of subsets first and exclude those that do not meet our criteria, which in this case are the single-element subsets and the empty set. Therefore, combinatory methods streamline the process of counting and organizing such subsets.

Mathematical Induction

Mathematical induction is a powerful proof technique used to establish the truth of an infinite sequence of propositions. While it's not explicitly employed in our exercise, understanding it can enhance the grasp of how certain mathematical truths are concluded, such as the formula for the number of subsets of a set (\(2^n\)).

Inductive reasoning starts with a base case, where the proposition is shown to be true. Then, it assumes that the proposition is true for some arbitrary case n, and on that basis, proves it is true for the next case n+1. This establishes a domino effect, confirming the proposition for all natural numbers. For the subsets of a set, one could use mathematical induction to show why the power set formula is always valid, thus cementing the basis for many combinatorial calculations.

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Problem 40 Let \(A\) be a set with 12 eleme... [FREE SOLUTION] (3)

Most popular questions from this chapter

In each of the following weighted voting systems, determine which players, ifany, have veto power. (a) \([9: 8,4,2,1]\) (b) \([12: 8,4,2,1]\) (c) \([14: 8,4,2,1]\) (d) \([15: 8,4,2,1]\)A professional basketball team has four coaches, a head\(\operatorname{coach}(H)\) and three assistant coaches \(\left(A_{1}, A_{2},A_{3}\right) .\) Player personnel decisions require at least three Yes votes,one of which must be \(H\) 's. (a) If we use \([q: h, a, a, a]\) to describe this weighted voting system, find\(q, h,\) and \(a\) (b) Find the Shapley-Shubik power distribution of the weighted voting system.A partnership has four partners \(\left(P_{1}, P_{2}, P_{3},\right.\) and\(\left.P_{4}\right) .\) In this partnership \(P_{1}\) has twice as many votes as\(P_{2} ; P_{2}\) has twice as many votes as \(P_{3} ; P_{3}\) has twice as manyvotes as \(P_{4} .\) The quota is a simple majority of the votes. Show that\(P_{1}\) is always a dictator. (Hint: Write the weighted voting system in theform \([q: 8 x, 4 x, 2 x, x],\) and express \(q\) in terms of \(x\) Considerseparately the case when \(x\) is even and the case when \(x\) is odd. \()\)The weighted voting system \([18: 10,8,6,4,2]\) represents a partnership amongfive people \(\left(P_{1}, P_{2}, P_{3}, P_{4},\right.\) and \(\left.P_{5}\right).\) You are \(P_{5},\) the one with two votes. You want to increase your power inthe partnership and are prepared to buy shares (one share equals one vote)from any of the other partners. (a) Suppose that each partner is willing to sell one share and that they areall asking the same price. Assuming that you decide to buy only one share,from which partner should you buy? Use the Banzhaf power index for yourcalculations. (b) Suppose that each partner is willing to sell two shares and that they areall asking the same price. Assuming that you decide to buy two shares from asingle partner, from which partner should you buy? Use the Banzhaf power indexfor your calculations. (c) If you have the money and the cost per share is fixed, should you buy oneshare or two shares (from a single person)? Explain.Equivalent voting systems. Two weighted voting systems are equivalent if theyhave the same number of players and exactly the same winning coalitions. (a) Show that the weighted voting systems \([8: 5,3,2]\) and \([2: 1,1,0]\) areequivalent. (b) Show that the weighted voting systems \([7: 4,3,2,1]\) and \([5: 3,2,1,1]\)are equivalent. (c) Show that the weighted voting system discussed in Example 2.12 isequivalent to \([3: 1,1,1,1,1]\) (d) Explain why equivalent weighted voting systems must have the same Banzhafpower distribution. (e) Explain why equivalent weighted voting systems must have the same Shapley-Shubik power distribution.
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Problem 40 Let \(A\) be a set with 12 eleme... [FREE SOLUTION] (2024)
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